LC.P420[强密码检验器]

方法一:模拟

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class Solution {
public int strongPasswordChecker(String password) {
char[] cs = password.toCharArray();
int n = cs.length;
int A = 0, B = 0, C = 0;
for (char c : cs) {
if (c >= 'a' && c <= 'z') A = 1;
else if (c >= 'A' && c <= 'Z') B = 1;
else if (c >= '0' && c <= '9') C = 1;
}
int m = A + B + C;
if (n < 6) {
return Math.max(6 - n, 3 - m);
} else if (n <= 20) {
int total = 0;
for (int i = 0; i < n; ) {
int j = i;
while (j < n && cs[j] == cs[i]) ++j;
int cnt = j - i;
if (cnt >= 3) total += cnt / 3;
i = j;
}
return Math.max(total, 3 - m);
} else {
int total = 0;
int[] cnts = new int[3];
for (int i = 0; i < n; ) {
int j = i;
while (j < n && cs[j] == cs[i]) ++j;
int cnt = j - i;
if (cnt >= 3) {
total += cnt / 3;
++cnts[cnt % 3];
}
i = j;
}
int base = n - 20, cur = base;
for (int i = 0; i < 3; ++i) {
if (i == 2) cnts[i] = total;
if (cnts[i] != 0 && cur != 0) {
int t = Math.min(cnts[i] * (i + 1), cur);
cur -= t;
total -= t / (i + 1);
}
}
return base + Math.max(total, 3 - m);
}
}
}
  • 时间复杂度:$O(n)$
  • 空间复杂度:$O(1)$