LC.P794[有效的井字游戏]

方法一:模拟

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class Solution {
public boolean validTicTacToe(String[] board) {
StringBuilder all = new StringBuilder();
int cntX = 0, cntO = 0;
for (String b : board) {
all.append(b);
for (int i = 0; i < b.length(); i++) {
char c = b.charAt(i);
if (c == 'X') cntX++;
else if (c == 'O') cntO++;
}
}
if (cntX != cntO && cntX != cntO + 1) return false;
if (win(all, 'X') && cntX != cntO + 1) return false;
if (win(all, 'O') && cntX != cntO) return false;
return true;
}

private boolean win(StringBuilder s, char c) {
// 横向
for (int i = 0; i < 9; i += 3) {
if (s.charAt(i) == c && s.charAt(i + 1) == c && s.charAt(i + 2) == c) {
return true;
}
}
// 纵向
for (int i = 0; i <= 2; ++i) {
if (s.charAt(i) == c && s.charAt(i + 3) == c && s.charAt(i + 6) == c) {
return true;
}
}
// 斜向
if (s.charAt(0) == c && s.charAt(4) == c && s.charAt(8) == c) {
return true;
}
if (s.charAt(2) == c && s.charAt(4) == c && s.charAt(6) == c) {
return true;
}
return false;
}
}
  • 时间复杂度:$O(C)$,$C = 9$
  • 空间复杂度:$O(C)$